how to use only wall clock?

How can I use only wall clock time if running a parallel solver? If I try to enter 0 for cpu time it says the minimum is 1.

Also, the max for cpu and wall clock are both 3600. Is there a way to get an exception for longer runs?

Would it make sense to run your job with CPU time = 4 * wallclock time? The max cpu time for all.q is currently 14400, or 4 times 3600. If we are displaying 3600 as the max cpu time, that is probably a bug.
Aaron

Sort of, but then I can't use a wallclock time bigger than max/4. Seems like I should just be able to turn off cpu time if I'm going to use wallclock time as my cut-off. But maybe that's what you want the max to be is total compute cycles per job pair?

I am not an expert of these matters, but if your solver takes cpu time greater than 4 * wallclock-timeout, wouldn't that imply you actually would have to exceed your wallclock timeout? If your solver is using all four cores the whole wallclock-timeout number of seconds, then it will rack up 4 * wallclock-timeout seconds of cpu time. Or am I wrong?
Aaron

Oh I misunderstood your previous post. You're suggesting wallclock 3600 and cpu 14400. Yes, that seems fine.

Exactly. Let me know if you run into any problems with that.
Aaron

OK I just tried 3600 wallclock and 14400 cpu and it worked. Thanks.